CPR
(MATH13- B10)

Members: C06 Wrenbria Ngo C07 Julie – Ann Parañal C08 Dani Patalinghog C09 Marino Penuliar C10 Michael Sadsad

CPR
(MATH13- B10)

Members: C06 Wrenbria Ngo C07 Julie – Ann Parañal C08 Dani Patalinghog C09 Marino Penuliar C10 Michael Sadsad

Prof. Charity Hope Gayatin
Prof. Charity Hope Gayatin

Homework 1.1

#15. Find the sides of each of the two polygons if the total number of sides of the polygons is 13, and the sum of the number of diagonals of the polygons is 25.
Assume: 8 and 5 D1= n2(n-3) …show more content…

SideA-SideB 28 =28cm – 17cm
17 x 90° = 11cm 19.52-112 Answer: 16.10 =380-121 =259 =16.10
Exercise 1.3 #7. A certain city block is in the form of a parallelogram. Two of its sides measure 32 ft. and 41 ft. If the area of the land in the block is 656ft.2, what is the length of its longer diagonal? A= 656ft.2
A= 656ft.2
Given:
32 ft. 41 ft. Required: d2=? Solution: For θ For d2 A = absin θ d2=a2+ b2 -2ab cos θ θ = sin-1656ft.2(32)(41) d2= (32)2+(41)2+2(32)(41)2 cos 150° θ = 30° d2=70.55105002 ft. θ = 150° Answer: d2=70.55 ft. #9. An isosceles trapezoid has an area 40m2 and an altitude of 2m. Its two bases have a ratio of 2 is to 3. What are the lengths of the bases and one diagonal of the trapezoid? d 2m d 2m
Given:
A= 40m2

3x Required: d=?
Solution: For x For d A = 12a+bh d = a2+b2 Answer: d = 2101 m 2(40) = (2x+3x)(2) d = 202+22 80 = (5x)(2) 10x = 80 d = 2101 x =